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When x is positive integer \(n\), harmonic_number
is
the \(n\)’th harmonic number. More generally,
harmonic_number(x) = psi[0](x+1) + %gamma
. (See polygamma).
(%i1) load("simplify_sum")$
(%i2) harmonic_number(5); 137 (%o2) --- 60
(%i3) sum(1/k, k, 1, 5); 137 (%o3) --- 60
(%i4) float(harmonic_number(sqrt(2))); (%o4) %gamma + 0.6601971549171388
(%i5) float(psi[0](1+sqrt(2)))+%gamma; (%o5) %gamma + 0.6601971549171388
Converts expressions with harmonic_number
to the equivalent
expression involving psi[0]
(see polygamma).
(%i1) load("simplify_sum")$
(%i2) harmonic_to_psi(harmonic_number(sqrt(2))); (%o2) psi (sqrt(2) + 1) + %gamma 0
Reduces the order of linear recurrence rec when a particular solution sol is known. The reduced reccurence can be used to get other solutions.
Example:
(%i3) rec: x[n+2] = x[n+1] + x[n]/n; x n (%o3) x = x + -- n + 2 n + 1 n
(%i4) solve_rec(rec, x[n]); WARNING: found some hypergeometrical solutions! (%o4) x = %k n n 1
(%i5) reduce_order(rec, n, x[n]); (%t5) x = n %z n n n - 1 ==== \ (%t6) %z = > %u n / %j ==== %j = 0 (%o6) (- n - 2) %u - %u n + 1 n
(%i6) solve_rec((n+2)*%u[n+1] + %u[n], %u[n]); n %k (- 1) 1 (%o6) %u = ---------- n (n + 1)! So the general solution is n - 1 ==== j \ (- 1) %k n > -------- + %k n 2 / (j + 1)! 1 ==== j = 0
Default value: true
If simplify_products
is true
, solve_rec
will try to
simplify products in result.
See also: solve_rec
.
Tries to simplify all sums appearing in expr to a closed form.
To use this function first load the simplify_sum
package with
load("simplify_sum")
.
Example:
(%i1) load("simplify_sum")$
(%i2) sum(binomial(n+k,k)/2^k, k, 1, n) + sum(binomial(2*n, 2*k), k, 1,n); n n ==== ==== \ binomial(n + k, k) \ (%o2) > ------------------ + > binomial(2 n, 2 k) / k / ==== 2 ==== k = 1 k = 1
(%i3) simplify_sum(%); 2 n - 1 n (%o3) 2 + 2 - 2
Solves for hypergeometrical solutions to linear recurrence eqn with polynomials coefficient in variable var. Optional arguments init are initial conditions.
solve_rec
can solve linear recurrences with constant coefficients,
finds hypergeometrical solutions to homogeneous linear recurrences with
polynomial coefficients, rational solutions to linear recurrences with
polynomial coefficients and can solve Ricatti type recurrences.
Note that the running time of the algorithm used to find hypergeometrical solutions is exponential in the degree of the leading and trailing coefficient.
To use this function first load the solve_rec
package with
load("solve_rec");
.
Example of linear recurrence with constant coefficients:
(%i2) solve_rec(a[n]=a[n-1]+a[n-2]+n/2^n, a[n]); n n (sqrt(5) - 1) %k (- 1) 1 n (%o2) a = ------------------------- - ---- n n n 2 5 2 n (sqrt(5) + 1) %k 2 2 + ------------------ - ---- n n 2 5 2
Example of linear recurrence with polynomial coefficients:
(%i7) 2*x*(x+1)*y[x] - (x^2+3*x-2)*y[x+1] + (x-1)*y[x+2]; 2 (%o7) (x - 1) y - (x + 3 x - 2) y + 2 x (x + 1) y x + 2 x + 1 x
(%i8) solve_rec(%, y[x], y[1]=1, y[3]=3); x 3 2 x! (%o9) y = ---- - -- x 4 2
Example of Ricatti type recurrence:
(%i2) x*y[x+1]*y[x] - y[x+1]/(x+2) + y[x]/(x-1) = 0; y y x + 1 x (%o2) x y y - ------ + ----- = 0 x x + 1 x + 2 x - 1
(%i3) solve_rec(%, y[x], y[3]=5)$
(%i4) ratsimp(minfactorial(factcomb(%))); 3 30 x - 30 x (%o4) y = - ------------------------------------------------- x 6 5 4 3 2 5 x - 3 x - 25 x + 15 x + 20 x - 12 x - 1584
See also: solve_rec_rat
, simplify_products
and product_use_gamma
.
Solves for rational solutions to linear recurrences. See solve_rec for description of arguments.
To use this function first load the solve_rec
package with
load("solve_rec");
.
Example:
(%i1) (x+4)*a[x+3] + (x+3)*a[x+2] - x*a[x+1] + (x^2-1)*a[x]; (%o1) (x + 4) a + (x + 3) a - x a x + 3 x + 2 x + 1 2 + (x - 1) a x
(%i2) solve_rec_rat(% = (x+2)/(x+1), a[x]); 1 (%o2) a = --------------- x (x - 1) (x + 1)
See also: solve_rec
.
Default value: true
When simplifying products, solve_rec
introduces gamma function
into the expression if product_use_gamma
is true
.
See also: simplify_products
, solve_rec
.
Returns the recurrence satisfied by the sum
hi ==== \ > summand / ==== k = lo
where summand is hypergeometrical in k and n. If lo and hi
are omitted, they are assumed to be lo = -inf
and hi = inf
.
To use this function first load the simplify_sum
package with
load("simplify_sum")
.
Example:
(%i1) load("simplify_sum")$
(%i2) summand: binom(n,k); (%o2) binomial(n, k)
(%i3) summand_to_rec(summand,k,n); (%o3) 2 sm - sm = 0 n n + 1
(%i7) summand: binom(n, k)/(k+1); binomial(n, k) (%o7) -------------- k + 1
(%i8) summand_to_rec(summand, [k, 0, n], n); (%o8) 2 (n + 1) sm - (n + 2) sm = - 1 n n + 1
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