problems with float

I think this can be done by
exp(exp(2.0))

or  exp(exp(2)),numer;

It seems to me that this facility is not
quite right though.
RJF


Daniel Lemire wrote:

> Maxima can't seem to evaluate numerically float(exp(exp(2))) .
> 
> (C30) float(exp(exp(2)));
> 
>                                                 2
>                                               %E
> (D30)                        2.718281828459045
> 
> 
> I used the following workaround:
> 
>   y(x) := EXP(FLOAT(EXP(x))) ROMBERG(EXP(- EXP(s)), s, 1, x)
> 
> Ugly!
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