>From Raymond Toy, Thu Aug 08, at 9:34:
. Paolo> which should yield %i
.I hope not.
.
Big pardon to all the matematicians on this list.
The result %i was what i expected from my computations so i forgot
to follow the correct procedure to compute (-1)^(1/6), that Harvey J. Stein has recalled.
Naively, i had decomposed (-1)^(1/6) into ( (-1)^(1/3) )^(1/2) = (-1)^(1/2) = %i
to quickly get the result i required.
I acknowledge tha all the remaing 5 results should be taken into account properly.
--
Paolo