Substitution question



I have the following function call in a more complicated expression:
erf((((64800 * %i + 64800) * t + 37 * %i + 35)/72))

I have another function acref, which takes 2 arguments, the first is the

argument of the error function and the second is a approximation order.
I want to substitute the call to acerf in place of erf in my more
complicated
expression, for example:
acerf((((64800 * %i + 64800) * t + 37 * %i + 35)/72), 2)
Is there a easy way to do this in maxima?
Thanks,
Dan Stanger