modulus

• Subject: modulus
• From: Poul Riis
• Date: Tue, 02 Dec 2003 18:29:46 +0100

<stavros.macrakis@verizon.net> skriver:
>rat(489)^2281,modulus:3293

I would like to define an operator like this:
infix(§);
a§b:=rat(a),modulus:b;

and then make for instance
489^2281§3293;

- but maxima won't accept it. How can I do it correctly?
I wonder why this operator is not a standard built-in operator in maxima?

Yours,
Poul Riis

• Prev by Date: result into multiple variables
• Next by Date: modulus
• Previous by thread: modulus
• Next by thread: modulus
• Index(es):
  • Date
  • Thread