How to get diff to yield result in terms of original function
Subject: How to get diff to yield result in terms of original function
From: Stavros Macrakis
Date: Fri, 9 Jan 2004 18:06:45 -0500
I misstated the * case, sorry. What I should have said is:
f(x):=q(x)*r(x)
qdiff(f(x),x) => f(x) * ( diff(q(x),x)/q(x) + diff(r(x),x)/r(x) )
And I would actually prefer that qdiff *not* quote its argument (which
is almost always a tricky interface), but rather use noun forms which it
would verbify as needed, e.g.
qdiff('f(x),x)