Another lame question : defining function by a result.



Hello,

It is just about the expectance of work. I want to
define a function f(x) by a result of previous
calculation, related to x. Example :
(%i1) 1 / ( x^3 - 1 );
				      1
(%o1) 				    ------
				     3
				    x  - 1
(%i2) integrate(%,x);
					 2 x + 1
		       2	    ATAN(-------)
		  LOG(x  + x + 1)	 SQRT(3)    LOG(x - 1)
(%o2) 	        - --------------- - ------------- +
----------
			 6	       SQRT(3)	        3
(%i3) f(x) := %o2;
(%o3) 				  f(x) := %o2
(%i4) f(10);
					 2 x + 1
		       2	    ATAN(-------)
		  LOG(x  + x + 1)	 SQRT(3)    LOG(x - 1)
(%o4) 	        - --------------- - ------------- +
----------
			 6	       SQRT(3)	        3

The x is not substituted by 10 in call %i4. Why ?

Thanx.
Jordan


		
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