eq:''diff(x + y =a, x);solve([eq],[dy/dx]);

• Subject: eq:''diff(x + y =a, x);solve([eq],[dy/dx]);
• From: Jorge Barros de Abreu
• Date: Sat, 23 Apr 2005 13:57:02 -0300

Hi for all.
How I make the following situation?

depends(y,x);
eq:''diff(x + y =a, x);
solve([eq01],[dy/dx]);

Thanks.

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