eq:''diff(x + y =a, x);solve([eq],[dy/dx]);
- Subject: eq:''diff(x + y =a, x);solve([eq],[dy/dx]);
- From: Jorge Barros de Abreu
- Date: Sun, 24 Apr 2005 20:48:32 -0300
There is no way to escape for (%i5) step ????
Em Sun 24 Apr 2005 20:31, Barton Willis escreveu:
> (%i1) algebraic : true;
> (%o1) true
> (%i2) depends(y,x);
> (%o2) [y(x)]
> (%i3) diff(x^(1/2) + y^(1/2) = a^(1/2), x);
> (%o3) 'diff(y,x,1)/(2*sqrt(y))+1/(2*sqrt(x))=0
> (%i4) solve(%,diff(y,x));
> (%o4) ['diff(y,x,1)=-sqrt(y)/sqrt(x)]
> (%i5) %*2*sqrt(y);
> (%o5) [2*sqrt(y)*('diff(y,x,1))=-(2*y)/sqrt(x)]
> (%i6) rat(%);
> (%o6) [2*sqrt(y)*('diff(y,x,1))=-(2*sqrt(x)*y)/x]