Using the Normal Distribution in Maxima



> > N(x) := erf(x/sqrt(2))/2.
>
> that should be N(x) := (1 + erf (x / sqrt(2)))/2 $ if i'm not mistaken.
>

or
N(x):= (1+erf( (x-m) / (s * sqrt(2) ) )/2

if you want to include the mean m and the standard deviation s>0.

-- 
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Mario Rodriguez Riotorto
www.biomates.net