How to solve expression containing trig, inverse trig and sqrt...

You seem to have a NUMERICAL problem, not a symbolic
problem.  Newton iteration might converge to a solution.
A program was posted to this mailing list a few weeks ago.
You can easily compute diff(f(t),t).

As far as an exact symbolic solution, it doesn't look
like a solution exists in closed form, though a proof of
that is not obvious.. there might be some trick.  But
Maxima does not do magic.  Just because you can ask a
question does not mean there is an assurance of getting
an answer.

Good luck!

RJF

Renaud AUBIN wrote:

> 
> Hello,
> 
> I'm a newbie and if the answer to my problem seems obvious, I'm sorry...
> 
> I have a geometrical problem to solve, i.e. I want to know the planar 
> parametric curve describes by a point submitted to geometrical 
> constraints. I have already obtained the parametric equations [ 
> fx(theta), fy(theta) ] but now, I want to solve fy(theta) - 
> fy(theta+phi) = 0 but I did not succeed in using sequently trigexpand, 
> trigsimp, trigreduce then solve...
> 
> Is in maxima a special way to do that, or have I to return to my 
> blackboard and try to solve my equation by myself ?
> 
> Here is my f(t) :
> 
> 0.029835*SIN(
> ATAN2(0.006*SIN(4*t+0.97222222222222*%PI)
> -0.006*SIN(4*t+0.34722222222222*%PI)
> ,0.006*COS(4*t+0.97222222222222*%PI)
> -0.006*COS(4*t+0.34722222222222*%PI)
> +0.04)
> 
> +ASIN(16.75884028825205*SQRT(
> (0.006*SIN(4*t+0.97222222222222*%PI)
> -0.006*SIN(4*t+0.34722222222222*%PI))^2
> +(0.006*COS(4*t+0.97222222222222*%PI)
> -0.006*COS(4*t+0.34722222222222*%PI)+0.04)^2)
> )
> 
> -%PI/2
> 
> )
> +0.006*SIN(4*t+0.34722222222222*%PI)
> 
> When I try to solve f(t)-f(t+phi) = 0 , phi as a known value (i.e. two 
> solutions exist) maxima does nothing than return to the next line with 
> an input prompt...
> 
> 
> Best regards,
> 
>