Question about long numbers



Richard Fateman wrote:

> I don't know why you need to input very long numbers, but
> you can always do this...
>
>   a*10^b+c*10^d+ ....
>
> for suitable a,b,c,d
>
> RJF
>
>
Yes your way does work and I would use it but I found that notpad works 
fine also.
the reason for the long numbers is that I believe I have found a proof 
that the logistic equation ( y=L*y(1-y) )
does not produce chaos.  I am just working out a couple of examples to 
go along with my results.
Is any one interested in this topic?   If  you are then we could email 
off list about it.