a newbe question ---- divide



Stavros Macrakis wrote:

> The solve routine assumes that any variables in a system of equations 
> are arbitrary parameters, not variables to be solved for.
>
> So, for example, solve([x=1,y=1],[x]); reports that equation 2 is 
> inconsistent.
>
> To solve your final equation, include all the variables:
>
>     solve([eq3,KD1,aa1],[KD,KP,a]);
>
OK. that makes sense.
Thanks.
Doug