That's a decent idea, I might try that.
Just for completeness, the Mathematica Notebook I am trying to port to
Maxima can be found here:
http://bigwww.epfl.ch/demo/Esplines/
It's probably trivial for someone who knows both packages, but I'm just
learning Maxima, and I don't even have Mathematica. (I'm just using
MathReader to view the notebook.)
Thanks,
-Frank
-----Original Message-----
From: maxima-admin at math.utexas.edu [mailto:maxima-admin at math.utexas.edu] On
Behalf Of Rogers, Raymond
Sent: Friday, January 06, 2006 9:56 AM
To: Frank Palazzolo
Cc: maxima at math.utexas.edu
Subject: RE: [Maxima] ilt()
Sorry about the empty message last time; finger twitch.
You might divide out the zero zero's and reinsert them after the transform
as differentiations. If that's not clear I could make a wrapper this
weekend; ilt_s(), or something.
Ray
> -----Original Message-----
> From: Frank Palazzolo [mailto:frank.palazzolo at mcm1.com]
> Sent: Thursday, January 05, 2006 10:21 AM
> To: 'Barton Willis'
> Cc: maxima at math.utexas.edu
> Subject: RE: [Maxima] ilt()
>
>
>
> Thanks! I knew it was something simple.
>
> -Frank
>
> -----Original Message-----
> From: Barton Willis [mailto:willisb at unk.edu]
> Sent: Thursday, January 05, 2006 9:15 AM
> To: Frank Palazzolo
> Cc: maxima at math.utexas.edu
> Subject: Re: [Maxima] ilt()
>
>
>
>
> ----Frank Palazzolo -----
>
> > For whatever reason, I can't get
> >ilt() to evaluate, even in a trivial case:
> >
> >ilt( s/(s+1), s, t);
> >
> >(This doesn't seem to do anything)
>
> This inverse Laplace transform involves a Dirac delta
> function--Maxima just
> gives up on such transforms. The function ilt isn't completely
> broken:
>
> (%i4) ilt( s/(s+1), s, t);
> (%o4) ILT(s/(s+1),s,t)
> (%i5) ilt( 1/(s+1), s, t);
> (%o5) %e^(-t)
>
> Barton
>
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