Re: [Maxima-bugs] [ maxima-Bugs-1407378 ] polarform returns a rectangular expression for float argumen

>
> Which, I think, makes sense.  And from looking at the code for
> $polarform, polarform doesn't really do anything to ensure
> %e^(0.78*%i) isn't simplified:
>

You're right.  I incorrectly assumed it did.

Along these lines, what do we think polarform(1) should return?  The
reasonable answers are:

      -- 1             (current result)
      -- %e^0       (simplify the 1* part)
      -- 1*1          (no good argument for this case, I don't think...)
      -- 1*%e^0    (no simplification at all to preserve the form)