integrate(x/(1-x^2),x)?



On Mon, Feb 13, 2006 at 01:42:05PM -0500, Raymond Toy wrote:
> 
> Maxima currently says
> 
> integrate(x/(1-x^2),x) ->
> -log(1-x^2)/2
> 
> and
> 
> integrate(x/(x^2-1),x) ->
> log(x^2-1)/2
> 
> What does Macsyma (or Mathematica/Maple) say for these integrals?

Mathematica says the same thing using
"integrals.wolfram.com/index.jsp" online.

Obviously this integral is only meaningful for certain regions of the
real line. For example maxima correctly says:

(%i6) integrate(x/(1-x^2),x,0,1);

Integral is divergent
 -- an error.  Quitting.  To debug this try debugmode(true);
(%i7) 

But I'm afraid I can't see what you're trying to say. Perhaps you
could clarify what you think it should do?

Since we're trying to find an indefinite integral here, maxima seems
like it's doing the right thing.



-- 
Daniel Lakeland
dlakelan at street-artists.org
http://www.street-artists.org/~dlakelan