partfrac( 1 / ( y^2 - 1 ) , y ) ; On 6/10/06, Roman <rvru at mega.ist.utl.pt> wrote: > how I can do this with Maxima? > > 1 > ------ => > 2 > y - 1 > > 1 1 > --------- - --------- > 2 (y - 1) 2 (y + 1)