Subject: Complex form formula of trigonometric functions
From: Barton Willis
Date: Mon, 23 Oct 2006 14:35:42 -0500
maxima-bounces at math.utexas.edu wrote on 10/18/2006 07:12:06 PM:
> Hello!
> Please, how I can do this and inverse transformation
> (exp(%i*x)-exp(-%i*x))/(2*%i) => sin(x)
> Roman
(%i13) rectform(exp(%i*x)-exp(-%i*x))/(2*%i);
(%o13) sin(x)
Barton