newbie question concerning recursion



On Fri, 2006-11-24 at 12:02 +0100, Hugo Coolens wrote:
> Thanks for the quick reply, I changed the syntax as you suggested but 
> entering zth[2]; gives:
> 
>   zth(1) s + 1
> 
> ------------------
> 
> (zth(1) + 1) s + 1 
that's because you only changed one of the 2 occurrences of
of zth(m-1) into zth[m-1]
You still have one more zth(m-1) to correct.

Jaime