Operations on inf



Make sure also that inf-inf returns undefined, instead of 0.

-Alasdair

On 3/8/07, Daniel Lakeland <dlakelan at street-artists.org> wrote:
>
> On Wed, Mar 07, 2007 at 03:54:24PM -0500, Stavros Macrakis wrote:
>
> > Why?  Both inf*inf and inf^2 go to inf regardless of how you approach
> it.
>
> if the inf^2 is going to be used in a further computation they may not
> be equivalent... such as limit(limit(x^2/(1+y^3),y,inf),x,inf) or
> something like that...
>
>
> --
> Daniel Lakeland
> dlakelan at street-artists.org
> http://www.street-artists.org/~dlakelan
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