Stavros Macrakis wrote:
>
>
> But inf^2 -> inf^2, still,
>
>
> Why? Both inf*inf and inf^2 go to inf regardless of how you approach it.
>
I meant that I'm not done yet. inf*inf uses simptimes, which is what
I've hacked on. inf^2 goes through simpexpt, which I haven't touched yet.
>
> and x*inf -> x*inf. I wasn't sure what to
> do with x*inf, so I thought it best to leave it alone.
>
>
What about x/inf? Is that 0 or x/inf? I think my version gives 0.
(Can't tell because I don't have the code right here.)
Ray