Operations on inf



On 3/11/07, Harald Geyer <Harald.Geyer at gmx.at> wrote:

> I agree. I think maxima should simplify what it can without ambiguity.
> (inf + inf = inf, etc)

Agreed.

> > Thus, though 1^inf and 0^0 may often be usefully taken as
> > 1, since in some situations (perhaps rare ones) that would lead to an
> > incorrect result, we must leave them as und and ind.
>
> I don't agree that this is the only possible conclusion. Why not
> just leave ambiguous cases like 0^0 alone instead of losing even more
> information?

Agreed.

Robert