<sen1 at math.msu.edu> schrieb:
> The 'expression based' system of maxima has its charm.
> Consider the following.
> %i26) f: x^3;
> 3
> (%o26) x
> (%i27) df(x):= diff(f,x);
> (%o27) df(x) := diff(f, x)
> (%i28) val(f,t):= subst(x=t,f);
> (%o28) val(f, t) := subst(x = t, f)
> (%i29) f: x^4;
> 4
> (%o29) x
> (%i30) df(x);
> 3
> (%o30) 4 x
> (%i31) val(f,2);
> (%o31) 16
> (%i32) val(df(x),5);
> (%o32) 500
Thanks, Sheldon, in addition to the other hints I am very happy with the solution now.
Your advice is in my opinion best combined with the abbreviate use of ev()=.,. (see J.
Villate) Thx you all.
HTH Wolfgang