is(1/(1-x) = -1/(x-1))



Hello,

in simplifying an expression, I came accross this:

$ maxima
Maxima 5.11.0 http://maxima.sourceforge.net
Using Lisp SBCL 1.0.3
Distributed under the GNU Public License. See the file COPYING.
Dedicated to the memory of William Schelter.
This is a development version of Maxima. The function bug_report()
provides bug reporting information.
(%i1) assume(x>0,x<1);
(%o1)                           [x > 0, x < 1]
(%i2) is(1/(1-x) = -1/(x-1));
(%o2)                                false
(%i3) radcan(1/(1-x));  
                                        1
(%o3)                               - -----
                                      x - 1

I would expect is(1/(1-x) = -1/(x-1)) to evaluate to true. Am I
missing something obvious here?