Ryan,
I don't think that the expression you expect to see is a correct
simplification of your original expression. They certainly evaluate to
different numerical values:
(%i1)
test:(L^3*(cos(beta)*sinh(beta)*L*c*s-cosh(beta)*sin(beta)*L*c*s+cos(beta)*s
inh(beta)*L*k-cosh(beta)*sin(beta)*L*k-2*beta*sin(beta)*sinh(beta)*EI))/(bet
a^3*EI*(cos(beta)*cosh(beta)*L*c*s+L*c*s+cos(beta)*cosh(beta)*L*k+L*k+beta*c
os(beta)*sinh(beta)*EI-beta*cosh(beta)*sin(beta)*EI))$
(%i2) test,beta=%pi/4,L=1,c=1,s=1,k=1,EI=1$
(%i3) %,numer;
(%o3) - 0.91779016483503
(%i4) test2:cos(beta)*cosh(beta)*L*(c*s+k)$
(%i5) test2,beta=%pi/4,L=1,c=1,s=1,k=1,EI=1$
(%i6) %,numer;
(%o6) 1.87328013886286
Generally, your friends in this case would be trigsimp, factor, expand,
trigexpand and trigreduce (to name a few), but of course, Maxima will not
produce a result (or so we hope!) that is mathematically not correct.
Viktor
-----Original Message-----
From: maxima-bounces at math.utexas.edu [mailto:maxima-bounces at math.utexas.edu]
On Behalf Of Ryan Krauss
Sent: Tuesday, May 15, 2007 5:36 PM
To: maxima list
Subject: factor/simplification problem
I have this expression
test:(L^3*(cos(beta)*sinh(beta)*L*c*s-cosh(beta)*sin(beta)*L*c*s+cos(beta)*s
inh(beta)*L*k-cosh(beta)*sin(beta)*L*k-2*beta*sin(beta)*sinh(beta)*EI))/(bet
a^3*EI*(cos(beta)*cosh(beta)*L*c*s+L*c*s+cos(beta)*cosh(beta)*L*k+L*k+beta*c
os(beta)*sinh(beta)*EI-beta*cosh(beta)*sin(beta)*EI))
and it has terms in the denominator like
cos(beta)*cosh(beta)*L*c*s+cos(beta)*cosh(beta)*L*k
I don't seem to be able to make Maxima factor/simplify this as
cos(beta)*cosh(beta)*L*(c*s+k)
which I would prefer. My knowledge of Maxima simplification is not
all that great, but poking around in the manual and searching the help
hasn't lead me to an answer I know how to use.
Can someone please help me with this?
Thanks,
Ryan
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