Simplify x^p^(1/p) to r?

To Maxima, x^y^z is x^(y^z) and not (x^y)^z. However, if you use
parentheses, you get

(%i1) (x^p)^(1/p);
                                      p 1/p
(%o1)                               (x )
(%i2) radcan(%);
(%o2)                                  x


Viktor

 

-----Original Message-----
From: maxima-bounces at math.utexas.edu [mailto:maxima-bounces at math.utexas.edu]
On Behalf Of Gary O
Sent: Friday, May 18, 2007 10:30 AM
To: maxima at math.utexas.edu
Subject: Simplify x^p^(1/p) to r?

Q: why doesn't this return x?
   ratsimp(x^p^(1/p))

If maxima doesn't know that x^y^z => x^(y*z), can I teach it somehow?

thanks,

-- Gary Oberbrunner
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