Mario gave you *the* solution to your Q1; nevertheless, for some other
problem, you might like to know the trick:
(%i1) x : [8.5,13.7,15,16,16.9,15.1,13.9,12]$
(%i2) y : [5.2,8.3,9.4,9.5,9.6,9.4,8.8,7.3]$
(%i3) map("[",x,y);
(%o3)
[[8.5,5.2],[13.7,8.300000000000001],[15,9.4],[16,9.5],[16.9,9.6],[15.1,9.4],[13.9,
8.800000000000001],[12,7.3]]
Barton
-----maxima-bounces at math.utexas.edu wrote: -----
To: "maxima-help" <maxima at math.utexas.edu>
From: Wolfgang Lindner
Sent by: maxima-bounces at math.utexas.edu
Date: 05/28/2007 06:37AM
Subject: contrib - descriptive - correlation coefficient
Q1: what is the most simple method to transform the splitted data
X:[8.5,13.7,15,16,16.9,15.1,13.9,12];
Y:[5.2,8.3,9.4,9.5,9.6,9.4,8.8,7.3];
into the above data_matrix_ XY as input for cov()?