map(rhs,a) On 6/11/07, Thomas Widlar <twidlar at yahoo.com> wrote: > > A beginner's question. Say I obtain a list *a* of solutions for *x*., e.g > . > > (%i19) a : solve(x^4-1); > (%o19) [x=%i,x=-1,x=-%i,x=1] > > How do I process *a* into a list *b* : [%i,-1,-%i,1] so I can say > > for x in b do something(x); >