reading integers from a stream



 

> -----Original Message-----
RJF:
> You may be able to read integers separated by new lines or by 
> spaces by
> using lisp.
> Try foo:?open(filename);
>  ?read(foo); ?read(foo); ....
> Getting the filename in the right form, as a string, may be tricky.
> RJF
>  
Hint  ...  Try   foo:?open(?"c:\\temp\\numbers")    for example.