Thanks!
I think it's better to perform it automatically while evaluating sum () if
simpsum is true. Will simplify_sum() be merged with sum () evaluation code?
On Monday 24 September 2007 21:46, you wrote:
> You can try the simplify_sum function. The cvs version returns will give
>
> (%i1) load(simplify_sum)$
> (%i2) simplify_sum( sum(1/n,n,1,inf) );
> (%o2) inf
> (%i3) simplify_sum( sum(1/(n+1),n,0,inf) );
> (%o3) inf
> (%i4) simplify_sum( sum(1/(n+6)-1/(n+8), n, 0, inf) );
> (%o4) 13/42
> On 9/24/07, Alexey Beshenov <al at beshenov.ru> wrote:
> > It seems that Maxima could not handle many simple cases of infinite sums.
> > For example,
> >
> > sum (1/n, n, 0, inf), simpsum;
> >
> > evaluates to inf, but
> >
> > sum (1/(n+1), n, 0, inf), simpsum;
> >
> > not evaluates, like many other simple things like
> >
> > sum (1/(n+6) - 1/(n+8), n, 0, inf), simpsum;
> >
> > Am I right and the problem is weak support of infinite sums?
--
Alexey Beshenov <al at beshenov.ru>
http://beshenov.ru/