Matrix: finding x in A.x=b

• Subject: Matrix: finding x in A.x=b
• From: Peter Danenberg
• Date: Wed, 21 Nov 2007 17:25:01 -0600

> Is there any way to find vector x in A.x=b simply?

What about something like this:

    (%i10) load(linearalgebra)$
    (%i11) A:matrix([1,2],[3,4])$
    (%i12) b:matrix([1],[2])$
    (%i13) lu_backsub(lu_factor(A, floatfield), b);

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