Subject: How to deal with r^(bfloat(2/3))/r^(2.0/3)
From: Richard Fateman
Date: Thu, 13 Dec 2007 07:53:57 -0800
Stavros has the right idea to look again at what you were doing.
A rule like changing numbers less than 1.0b-16 to zero is questionable. But
then any use of r^(float) in Maxima is unusual, so maybe nothing else will
break.