Can Maxima solve x*exp(-x) = 0.05 ?



On Feb 1, 2008 11:31 AM, Paul Smith <phhs80 at gmail.com> wrote:
> Is there some trick to have Maxima solving the following equation:
>
> f(x):=x*exp(-x)-0.05;
> solve(f(x),x);
>
> ?

Well, with plot2d I identified the localization of the roots and then
I got the value of them with:

find_root(f(x),x,2,5);
find_root(f(x),x,0,2);

Paul