It works. Many thanks for the solution and for the explanation. Robert
On Sat, Mar 22, 2008 at 10:25 PM, Alasdair McAndrew <amca01 at gmail.com>
wrote:
> I think if your factorization is not over the rationals, you have to tell
> Maxima what field extension to use. This sort of works:
>
> p:partfrac(1/factor(x^3+2,a^3-2),x);
> subst(2^(1/3),a,p);
>
> This first expression helps partfrac by extending the field of rationals
> by the cube root of 2.
>
> cheers,
> Alasdair
>
>