Subject: Can Maxima do Operators Like the Hamiltonian
From: Richard Hennessy
Date: Thu, 17 Apr 2008 01:53:13 -0400
I came up with this for the one dimensional case
H(f):=-diff(f,x,2)*hbar^2/(2*m)+v(x)*f;
Is there a better way, this is just a function really and you use it like this
f(x):=x^2;
H(f(x)) = Hamiltonian
Rich