Thank you - that's really nice and elegant. Someday... I should really
learn some lisp!
-Alasdair
On Fri, May 2, 2008 at 2:20 AM, Zach <elzacho at gmail.com> wrote:
>
> What about using Lisp's number parsing facilities. I'm not smart enough
> with Maxima to see a pretty way of doing this, but certainly:
>
> (%i45) :lisp #x1000
> 4096
> (%i45) :lisp #xFF24
> 65316
>
> It is easy to write Lisp function that takes a string of hex and converts
> it to decimal:
>
> :lisp (defun $hex_to_dec (hex-string) (read-from-string (concatenate
> 'string "#x" hex-string)) )
>
> (notice that this is all on one line)
>
> hex_to_dec("FF24");
> ==> 65316
>
> Sorry if this is redundant,
> Zach
>
>
> On Fri, Apr 25, 2008 at 6:01 PM, Robert Dodier <robert.dodier at gmail.com>
> wrote:
>
> > On Fri, Apr 25, 2008 at 4:08 PM, Alasdair McAndrew <amca01 at gmail.com>
> > wrote:
> >
> > > I have some long hexadecimal numbers (48 hex digits) I want to use.
> > But
> > > ibase:16 doesn't seem to accept non-numeric characters as input:
> >
> > Yes, there is no way to enter a, b, c, ... for digits when ibase > 10.
> > This came up recently; see:
> > http://article.gmane.org/gmane.comp.mathematics.maxima.general/20490
> >
> > The patch mentioned in that message yields
> > stuff like 1b0 => ibase^2 + 11*ibase when it should be bfloat(1)
> > (as it is when ibase=10). I've tinkered some more to try to prevent
> > surprises like that but I haven't gotten it nailed down.
> > If someone else wants to try it, that would be great.
> >
> > Hope this helps,
> >
> > Robert Dodier
> > _______________________________________________
> > Maxima mailing list
> > Maxima at math.utexas.edu
> > http://www.math.utexas.edu/mailman/listinfo/maxima
> >
>
>