My answer is wrong if you want to leave the value of the expression unchanged. My point was that you can do many things manually in Maxima if you want.
To divide both sides of an equation by sqrt(x+h)
eq:sqrt(x)=x^2-5;
%/sqrt(h+h); does the trick
the same idea applies to +-*/^
Rich
------------Original Message------------
From: "Ronald Modesitt" <rmodesi at msn.com>
To: "'Richard Hennessy'" <rvh2007 at comcast.net>
Date: Thu, May-8-2008 10:01 AM
Subject: RE: [Maxima] Maxima algebraic simplification
Richard,
Thanks again. I am really impressed with the quality support for Maxima. Especially the tolerance for newbies.
Ron
-----Original Message-----
From: Richard Hennessy [mailto:rvh2007 at comcast.net]
Sent: Thursday, May 08, 2008 2:01 AM
To: Ronald Modesitt; maxima at math.utexas.edu
Subject: Re: [Maxima] Maxima algebraic simplification
An oversight
Try
(sqrt(x+h)-sqrt(x))/h;
% / (sqrt(x+h)-sqrt(x));
radcan(%);
-> 1/(h*(sqrt(x+h)-sqrt(x)))
------------Original Message------------
From: "Richard Hennessy"<rvh2007 at comcast.net>
To: "Ronald Modesitt" <rmodesi at msn.com>, maxima at math.utexas.edu
Date: Thu, May-8-2008 3:25 AM
Subject: Re: [Maxima] Maxima algebraic simplification
Why do you want to make the numerator 1?
Anyway an answer is
(sqrt(x+h)-sqrt(x))/h;
% / (sqrt(x+h)-sqrt(x));
-> 1/(h*(sqrt(x+h)-sqrt(x)))
Rich
------------Original Message------------
From: "Ronald Modesitt" <rmodesi at msn.com>
To: maxima at math.utexas.edu
Date: Wed, May-7-2008 9:15 PM
Subject: Maxima algebraic simplification
Hi all, more questions from a newbie reviewing calculus:
If F(x)=sqrt(x), then
F(x+h) =sqrt(x+h) and
(F(x+h) ?F(x))/h = (sqrt(x+h) ?sqrt(x))/h.
To set the numerator to 1 we multiply thru by
sqrt(x+h) + sqrt(x)/((sqrt(x+h) +sqrt(x))
this yields
1/(sqrt(x+h) + sqrt(x)).
My question is this. How do I ask Maxima to set the numerator to a specific value, in this case 1?
Ron
Ronald F. Modesitt, PE
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