The fourth argument is only used for finite limits. For exampe,
limit(1/x,x,0,plus) ? inf and ...minus ? minf. To specify a limit as x
goes to minus infinity, use limit(x,x,minf).
Though I suppose Maxima could treat "the point at infinity" just like
a finite real, it doesn't. If it did, though, to be consistent,
wouldn't limit(-x^2,x,inf) have to be the point inf?
-s
On 5/12/08, Ronald Modesitt <rmodesi at msn.com> wrote:
> Hi all,
>
> Help me understand this inconsistency?
>
>
>
> (%i34) limit(2^x,x,inf,plus);
>
> (%o34) inf
>
>
>
> (%i35) limit(2^x,x,inf,minus);
>
> (%o35) inf - why isn't this '-inf' ?
>
>
>
> Ron
>
>
>
>
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