Thanks a lot! format(e,%poly(x,z)); did the job
Bye,
Andreas
Richard Fateman wrote:
> there is actually no reason to expect Maxima to "simplify" an expression to
> some arbitrary form that you happen to like;
> Maxima has its own particular repertoire of "kinds of simplifications" and
> getting exactly the ordering you want may be contrary to its rules. On the
> other hand, there is a package that tries to come up with a formatting
> arrangement that might allow for something like this form. Bruce Miller
> wrote it, and it is called format. e.g. load(format) does it.
> documentation?? see http://math.nist.gov/~BMiller/computer-algebra/
>
>
>> -----Original Message-----
>> From: maxima-bounces at math.utexas.edu
>> [mailto:maxima-bounces at math.utexas.edu] On Behalf Of Andreas Kranz
>> Sent: Tuesday, May 27, 2008 1:08 PM
>> To: maxima at math.utexas.edu
>> Subject: Simplification question
>>
>> Hello,
>>
>> as a maxima newbie I've trouble understanding how to achieve
>> a certain
>> transformation.
>>
>> Especially I would like the following term:
>>
>> 2 vx z - r z - l z - 2 n (x - vx) - 2 vz x + r vz + l vz
>> - --------------------------------------------------------
>> r - l
>>
>> to be written as:
>>
>>
>> 2(n + vz) -2 vx r + l 2 n vx + r vz + l vz
>> --------- x + (----- + -----) z + --------------------
>> r - l r - l r - l r - l
>>
>>
>> probably an easy task for maxima but maybe I'm just to blind
>> to see how
>> to do this.
>> I've already experimented with combinations of factorsum,
>> factorout and
>> friends but
>> could not work that out.
>>
>> Any suggestions?
>>
>> Bye,
>>
>> Andreas
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