Mathematica to Maxima translation is a derivative work

It may well be though, that Wolfram maintains copyright on some of their
algorithms.  If that is the case, they could take legal action if one of
their algorithms was used in an open-source product.  I had a similar
problem a few years ago, when I tried rewriting an algorithm from "Numerical
Recipes" in Maxima.  It turns out that the algorithm - as presented in NR -
was copyright, and so I couldn't use it in Maxima.

-Alasdair


On Mon, Sep 15, 2008 at 8:47 AM, Harald Geyer <harald at lefant.net> wrote:

>
> > I think that creating a derivative work, such as a translation from
> > Mathematica to Maxima is copyright by Mma, so who to sue in case of
> > problems?
>
> I'm not aware that anybody is creating or distributing derivative work
> from Mathematica.
>
> In case anybody is distributing work copyrighted by Wolfram Research
> without license, he might be in legal trouble soon.
>
> I think you have no clue what you are talking about. There is no such
> thing as a copyright by Mma.
>
> HTE,
> Harald
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