On Sept. 23, Raymond Toy wrote;
> Edwin Woollett wrote:
>> In the manual under quad_qag and quad_qags the statement:
>> "(limit - limlst)/2 is the maximum number of subintervals to
>> use. Default is 200."
>>
>> Since this refers to the keyword "limit", is the default value
>> of limit equal to 200 or does this mean (limit - limlst)/2 ?
>>
>> What is the value of limlst?
>
> Had to look up the Fortran source code to find out.
>
> It's an error in the documentation. There is no limlst for qag and
> qags. So limit defaults to 200 and is the maximum number of subintervals.
>
> limlst appears to be only used by qawf.
>
> Ray
>
Thanks for the information about "limlst" use.
My review of the quad_qaxx section of manual
shows that, according to the manual,
*both* quad_qawf and quad_qawo use
and define limlst as "Upper bound on
the number of cycles. Must be greater than
or equal to 3. Default is 10. ",
but neither define what is meant by "cycles".
Moreover, both _qawf and _qawo have the confusing definition of "limit".
Of the other five quad_qaxx functions, only one ( _qaws) has a coherent
definition of "limit".
Ted Woollett