Subject: how to solve for an implicit derivative --
From: shorne at energetiq.com
Date: Tue, 21 Oct 2008 11:53:54 -0400
Hello maxima users --
This should be easy but in a couple hours of messing around I haven't
figured it out -
f(x,y)=0;
depends(y,x);
eq1: diff(f,x);
(gves an expression involving dy/dx)
How can I
solve(eq1, dy/dx);
I'm asking here about syntax -- I understand that for many choices of f,
solve will fail.
For discussion, take f(x,y) = x^2 + y^2 -1.
Thanks,
Steve