I want integrate(pwdelta(x),x,minf,0) 1/2 and integrate(pwdelta(x),x,0,inf) 1/2 I can try making integrate(pwdelta(x),x) = (signum(x)+1)/2 that should work but does not partly because limit(signum(x),x,inf) cannot be computed. Is there a work around? FYI I want these two integrals to be true by definition (of pwdelta)! Rich