I want
integrate(pwdelta(x),x,minf,0)
1/2
and
integrate(pwdelta(x),x,0,inf)
1/2
I can try making
integrate(pwdelta(x),x) = (signum(x)+1)/2
that should work but does not partly because limit(signum(x),x,inf) cannot be computed. Is there a work around?
FYI I want these two integrals to be true by definition (of pwdelta)!
Rich