Dieter Kaiser wrote:
> Am Sonntag, den 01.03.2009, 01:31 +0100 schrieb Dieter Kaiser:
>
......
>>
>
> With the fix which has Dan Gildea checked in today the Laplace
> transformation of sin(t)/t^2 works as expected. We get the noun form and
> $laplace no longer hangs:
>
> (%i3) laplace(sin(t)/t^2,t,s);
> (%o3) 'laplace(sin(t)/t^2,t,s)
>
Mathematica 6.0 gives this answer..
(2 - 2*EulerGamma + (-1 - I*s)*Log[-I + s] + I*(I + s)*Log[I + s])/2
RJF