Dear all
I find there is a question on "%" output type
for example
(%i96) x^2+x+1;
(%o96) x^2+x+1
(%i97) eq1:%;
(%o97) x^2+x+1
(%i98) f(x):=%;
(%o98) f(x):=%
why f(x) can not assign by %.
if the "%" output type can not use in "f(x):=" that were be not a convience in programming.
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