Hello,
I need to substitute a function into equation, which integrates a function being substitued.
Let say:
eqq:integrate(F(t),t,0,1)=a;
I thought that
ev(subst(sin(t), F(t), eqq), 'nouns);
would give me
1-cos(1)=a
(as from integrate(sin(t),t,0,1)=a;)
but it just writes integral as it is without evaluating it.
I also tried
ev(eqq, F(t):=sin(t));
with the same result.
Thanks for any ideas,
Konstantin Malakhanov
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Konstantin Malakhanov