viewing function image f(U)



You can try plotting the bounds of f([a,b]x[c,d]) to display its shape.
for example:
f(x,y) := [x, x*y];
a : 1;
b : 3;
c : 1;
d : 4;
plot2d([[parametric, f(t,c)[1], f(t,c)[2], [t, a, b]],
	[parametric, f(t,d)[1], f(t,d)[2], [t, a, b]],
	[parametric, f(a,t)[1], f(a,t)[2], [t, c, d]],
	[parametric, f(b,t)[1], f(b,t)[2], [t, c, d]]],
	[x, 0, 15], [y, 0, 15]);

On May 24, 2009, at 9:01 PM, Antonio Ragagnin wrote:

> Hi, i'm solving some integrals. when i change variables i'm not good
> to see the new domain of the integration.
> for example, if the initial domain was a rectangle [a,b]x[b,c]
> and i change it to another thing with f(x,y)=[x,x*y]
>
> how can i know the shape of the new domain f([a,b]x[c,d])?
>
> thanks!
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