Stavros Macrakis pisze:
> Yes, but you must have some way of generating the sublists and lists.
> What is that way?
I do it ( or try to do) in this way :
1. make a empty list
a:[];
2. add empty sublist to list
a:cons([],a);
Adam
>
> On Mon, Jun 1, 2009 at 4:18 PM, Adam Majewski <adammaj1 at o2.pl> wrote:
>
>
> Thx for answer.
> > Depends where the elements are coming from. If you know what
> they are
> > in advance...
> I do not know how many sublists it will be
> and I don't know the elements of sublists.
>
> Adam
>
> >
> > a: [ [c] , [d] ] $
> >
> > Or you can do things like
> >
> > makelist( makelist(i,i,1,n), n, 1, 4)
> > => [[1], [1, 2], [1, 2, 3], [1, 2, 3, 4]]
> >
> > On Mon, Jun 1, 2009 at 3:49 PM, Adam Majewski <adammaj1 at o2.pl> wrote:
> >
> > Hi,
> >
> > I wanted to make array of list, but I failed to do it
> > so I've tried to make list of lists ( if it is possible).
> >
> > Here is what I have done :
> > 1. make a empty list
> > a:[];
> > 2. add elements to list ( another empty list)
> > a:cons([],a);
> > a:cons([],a);
> > 3. add elements to sublists
> > a[1]:cons(c,a[1]);
> > a[2]:cons(d,a[2]);
> > 4. check
> > a[1][1];
> >
> > Is it a good/best way ?
> >
> > Adam
> >
> >
> > ============== code ====================
> > a:[];
> > a:cons([],a);
> > a:cons([],a);
> > a[1]:cons(c,a[1]);
> > a[2]:cons(d,a[2]);
> > a[1][1];
> > ==============================================
> >
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