True. I suppose I was expecting it to return the case with the polynomial
made explicit, e.g.
solve(%e^(5*x)+%e^(2*x)+1,x) =>
[ %e^x = %r1, %r1^5+%r1^2+1 = 0 ]
but I don't know why I was expecting that -- Maxima has never done this sort
of transformation for the user....
-s
On Thu, Jun 11, 2009 at 9:40 AM, Richard Fateman <fateman at cs.berkeley.edu>wrote:
> Stavros Macrakis wrote:
>
>> ..
>>
>
>
>
>>
>> Pull out %e^r (why can't solve do this?)
>>
>
> It can, especially if solveradcan : true. However it is still of degree
> 5.
>
>
>