Robert Dodier wrote:
> Hi, is there some way to simplify stuff like this?
>
> binomial((t + 1)*(n + 1), n + 1)/binomial((t + 1)*n, n)
>
> On a related note, I couldn't figure out a way to get (n + 1)!/n! to
> yield (n + 1).
> I'm probably overlooking something obvious.
>
>
makefact will convert the binomials to factorials.
minfactorial((n+1)!/n!) -> n+1
But these don't really simplify your binomials.
Ray